Answer to Question #57696 in General Chemistry for Siobhan Gilheany
Explain how to prepare 800 ml of 0.78 mmol/litre NAD+ (MW 655.43) solution.
ν (NAD+) = 0.78 x 0.8 = 0.624 mmol
m (NAD+) = 0.624 x 10-3 x 655.43 = 0.409 g
Answer: For 800 ml 0.78 mmol/L NAD+ (655.43) need 0.409 g NAD+.
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