Answer to Question #56300 in General Chemistry for Emily

Question #56300
What is the mass of 0.060 eq of NiAsO3 (with a molar mass of 182 g/mol) and how do you solve this?
Expert's answer
It is salt of trivalent arsenite-anion AsO33- and Ni3+ cation. In this case each mole of this salt represents to 3 equivalents (due to anion and cation valencies).
n = 3 * 0.060 eq = 0.180 mol
m = n MW = 0.180 mol * 182 g/mol = 32.76 g ≈ 32.8 g

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