Question #56300

What is the mass of 0.060 eq of NiAsO3 (with a molar mass of 182 g/mol) and how do you solve this?

Expert's answer

It is salt of trivalent arsenite-anion AsO_{3}^{3-} and Ni^{3+} cation. In this case each mole of this salt represents to 3 equivalents (due to anion and cation valencies).

n = 3 * 0.060 eq = 0.180 mol

m = n MW = 0.180 mol * 182 g/mol = 32.76 g ≈ 32.8 g

n = 3 * 0.060 eq = 0.180 mol

m = n MW = 0.180 mol * 182 g/mol = 32.76 g ≈ 32.8 g

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