Question

would these equations and ionic equations be correct along with the states thank you
2Kl(aq) + Cl2 (aq) 2KCl (aq) + I2 (aq)
ionic 2I-(aq) + Cl2(aq) ---> I2(aq) + 2Cl-(aq)

Br2(aq) + 2KI(aq) -> 2KBr(aq) + I2 (aq)
ionic 2I- (aq) + Br2 (aq) --> 2Br-(aq) + I2(aq)

Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
ionic Fe(s) + 2H+(aq) → Fe 2+(aq) + H2(g)

Cu(s) + 2HCl(g) → CuCl2(s) + H2(g)
ionic Cu(s) + 2H+(aq) → Cu 2+ + H2(g)

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
ionic Zn(s)+2H+(aq) = Zn2+(aq) + H2(g)

Answer 1

Here are the correct reactions and states:
2Kl(aq) + Cl₂(g) → 2KCl(aq) + I₂(s)
ionic 2I^-(aq) + Cl₂(g) → 2Cl^-(aq) + I₂(s)
Br₂(l) + 2KI(aq) → 2KBr(aq) + I₂(s)
ionic Br₂(l) + 2I^-(aq) → 2Br^-(aq) + I₂(s)
Fe(s) + 2HCl(aq) → FeCl₂(aq) + H₂(g)
ionic Fe(s) + 2H⁺(aq) → Fe²⁺(aq) + H₂(g)

Cu(s) + 2HCl(aq) → CuCl₂(aq) + H₂(g)
ionic Cu(s) + 2H⁺(aq) → Cu²⁺(aq) + H₂(g)

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
ionic Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)