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Answer to Question #56295 in General Chemistry for tracy guido

Question #56295
would these equations and ionic equations be correct along with the states thank you
2Kl(aq) + Cl2 (aq) 2KCl (aq) + I2 (aq)
ionic 2I-(aq) + Cl2(aq) ---> I2(aq) + 2Cl-(aq)

Br2(aq) + 2KI(aq) -> 2KBr(aq) + I2 (aq)
ionic 2I- (aq) + Br2 (aq) --> 2Br-(aq) + I2(aq)

Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
ionic Fe(s) + 2H+(aq) → Fe 2+(aq) + H2(g)

Cu(s) + 2HCl(g) → CuCl2(s) + H2(g)
ionic Cu(s) + 2H+(aq) → Cu 2+ + H2(g)

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
ionic Zn(s)+2H+(aq) = Zn2+(aq) + H2(g)
Expert's answer
Here are the correct reactions and states:
2Kl(aq) + Cl2(g) → 2KCl(aq) + I2(s)
ionic 2I-(aq) + Cl2(g) → 2Cl-(aq) + I2(s)
Br2(l) + 2KI(aq) → 2KBr(aq) + I2(s)
ionic Br2(l) + 2I-(aq) → 2Br-(aq) + I2(s)
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
ionic Fe(s) + 2H+(aq) → Fe2+(aq) + H2(g)

Cu(s) + 2HCl(aq) → CuCl2(aq) + H2(g)
ionic Cu(s) + 2H+(aq) → Cu2+(aq) + H2(g)

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
ionic Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)

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