Answer to Question #56207 in General Chemistry for jocelyn
ν(HAc) = ν(NaOH) = C(NaOH)×V(NaOH) = 0.1067 mol/L × 0.03648 ml = 3.8924 mmol
The mass of acetic acid is:
m(HAc) = ν(HAc)×M, where M - the molar weight of acetic acid.
m(HAc) = 3.8924 mmol × 60 g/mol = 233.54 mg (in 5 ml).
In 1 L the mass of acetic acid is:
m(HAc) = (1000/5)× 233.54 mg = 46.71 g
Thus, the mass % of acetic acid is determined:
w(%) = m(HAc)/1000 × 100% = 4.67%
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