Question #206680

Calculate the entropy change, in melting of ice at 0˚C.(heat of fusion of ice is 6.02 kJ/mol)

Expert's answer

This heat is absorbed at the constant temperature T=0+273.15=273.15 K.

The entropy increase in the process:

"\u0394S = \\frac{\u0394H}{T} \\\\\n\n= \\frac{6.02 \\times 10^3}{273.15} \\\\\n\n= 22.04 \\;J\/mol\\;K"

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