120 grams of sodium hydroxide completely reacts with phosphoric acid (H3PO4) in the reaction 3 NaOH + H3PO4 -> Na3PO4 + 3 H2O what mass of water is produced?
Moles of Sodium hydroxide
= 120 / 40 =3 mol.
3 mol. Of NaOH gives 3 mol . Of water
Mass of water formed = 3 × 18 = 54 g .
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