Answer to Question #202381 in General Chemistry for jordan

Question

1. If you had 6.50 moles of ferric hydroxide how many grams of ferric sulfate will be produced?

2. If 25.7 grams of water was produced what is the amount of sulfuric acid needed to produce the

water?

Answer 1

a)4FeSO₄ + 3H₂O-->> 2Fe₂(OH)₃ + 4SO₂ + SO₃

Mole ratio = 4FeSO₄ = 2Fe₂O₃

Molar Mass of FeSO₄ = 151.908

= 6.50 × 2 × 151.908

= 1974.804g

b) Zn + H2SO4 → ZnSO4 + H₂O

Mole ratio = 1:1

Molar Mass of H₂O = 18.01528

= 25.7/18.01528

= 1.43 moles

Molar Mass of H2SO4 = 98.079

= 1.43 × 98.079

= 139.92g