Question #200311

Zinc reacts with hydrochloric acid to form zinc chloride and hydrogen. What mass of zinc chloride could be produced if 25cm^{2} of hydrochloric acid of concentration 2.4 mol dm‐³ reacts with excess zinc

Expert's answer

The reaction could be expressed as:

"Zn+2HCl\\rightarrow ZnCl_{2}+H_{2}"

The amount of HCl in moles is:

"\\nu(HCl)=V(HCl)\\cdot C(HCl)=0.025 dm^{3}\\cdot2.4mol\/dm^{3}=0.06 mol;"

The amount of ZnCl_{2} in moles is:

"\\nu(ZnCl_{2})=\\frac{1}{2}\\cdot\\nu(HCl)=0.03mol;"

The molar mass of ZnCl_{2} is:

"M(ZnCl_{2})=136g\/mol;"

Thus, the mass of ZnCl_{2} produced is:

"m(ZnCl_{2})=\\nu(ZnCl_{2})\\cdot M(ZnCl_{2})=4.08g."

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