Question #200239

C_{3}H_{8} + 5O_{2} --> 3CO_{2} + 4 H_{2}O

Using the above reaction, calculate how many grams of H_{2}O_{ }will be made if 195.0 g of O_{2} is reacted?

Expert's answer

MM(O_{2}) = 32 g/mol

n(O_{2}) "= \\frac{195}{32}=6.093 \\;mol"

According to the reaction:

n(H_{2}O) "= \\frac{4}{5}n(O_2) = \\frac{4}{5} \\times 6.093 = 4.875 \\;mol"

MM(H_{2}O) = 18 g/mol

m(H_{2}O) "= 4.875 \\times 18 = 87.75 \\;g"

Answer: 87.75 g

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