Question #199560

**1. **Upon heating, NaN_{3(s)} decomposes to Na_{(l)} and N_{2(g)}. This reaction serves as a convenient laboratory preparation of pure nitrogen gas.

2 NaN_{3(s)} ¾® 2 Na_{(l)} + 3 N_{2(g)}

a) What number of moles of NaN_{3} is required to prepare 1.00 mol of N_{2}?

b) What mass of N_{2} is produced by the decomposition of 2.00 mol NaN_{3}? (

c) What mass of Na is produced when 1.75 g of N_{2} is prepared?

Expert's answer

We have given the reaction:

"2NaN_3 \\rightarrow 2Na+3N_2"

a.) 3 moles of "N_2" gives 2 moles of "NaN_3"

1 mole of "N_2 \\hspace{1mm} gives = \\dfrac{2}{3 }" moles of "NaN_3"

b.) 2 moles of "NaN_3" gives 1 mole of "N_2"

1 mole of "NaN_3" give "= \\dfrac{1}{3}" moles of "N_2 = \\dfrac{1}{3} \\times 28"

c.) Similarly we can also this part also.

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