Question #199253

Calculate the molality of a 19% HF aqueous solution. What is the ppm of HF in this solution?

Determine the mass percentage and ppm of a 0.333m NaCl solution.

Calculate the molarity of a 0.85m lithium chloride aqueous solution having a density of 1.44 g/mL

Expert's answer

Calculate Molality of HF

1) Let us assume 100.0 gram of solution. Therefore:

19gm is HF

81gm is H_{2}O

2) Molality is:

moles HF = 19gm/20.0059 g/mol = 0.95 mol

kg of water = 0.0810 kg

mololity = 0.95 mol/0.0810 kg = _{ }1.172 molal

ppm=

= 19000ppm

Calculate Mass Percentage of NaCl

1) moles of NaCl Solution given = 0.333 mol

molecular weight of NaCl = 0.333 58.44

= 19.46 g

2) so mass percentage of NaCl is

so

mass percentage= 1.946% NaCl.

ppm =

= 19460ppm

Calculate Molarity of lithium chloride

1) Molarity in terms of molality

so,

solve above equation

molarity = 1.187 M

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