Calculate the molality of a 19% HF aqueous solution. What is the ppm of HF in this solution?
Determine the mass percentage and ppm of a 0.333m NaCl solution.
Calculate the molarity of a 0.85m lithium chloride aqueous solution having a density of 1.44 g/mL
Calculate Molality of HF
1) Let us assume 100.0 gram of solution. Therefore:
19gm is HF
81gm is H2O
2) Molality is:
moles HF = 19gm/20.0059 g/mol = 0.95 mol
kg of water = 0.0810 kg
mololity = 0.95 mol/0.0810 kg = 1.172 molal
Calculate Mass Percentage of NaCl
1) moles of NaCl Solution given = 0.333 mol
molecular weight of NaCl = 0.333 58.44
= 19.46 g
2) so mass percentage of NaCl is
mass percentage= 1.946% NaCl.
Calculate Molarity of lithium chloride
1) Molarity in terms of molality
solve above equation
molarity = 1.187 M