Question #195268

Determine the concentration of a solution (in % by mass, % by volume, % by mass

volume, molarity, molality and ppm) containing 5 grams of NaCI and 50 ml of water.(p of NaCl = 2.1 g/ml,p of water = 1g/ml).What is the mole fraction of NaCI in the solution?

Expert's answer

Ans:-

Given "5" grams of "NaCI" and "50 ml" of water

Moles of "NaCl=\\dfrac{5}{58.4}=0.0856mol"

Concentration of Solution in molarity"=\\dfrac{Moles of Sollution}{volume of solution}=\\dfrac{0.0856}{50}\\times1000=1.7123M"

Concentration of Solution in molality"=\\dfrac{moles of solute}{Mass of Solvent}=\\dfrac{0.0856}{50}\\times1000=1.7123m"

We know that density of Water is "1g\/ml".

So, mass of Water present in solution "=" density"\\times" volume"=1\\times50=50g"

Hence moles of water"=\\dfrac{50}{18}=2.77mol"

Mole fraction of "NaCl" in solution"= \\dfrac{0.0856}{0.0856+2.77}=0.03"

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