Question #192832

Determine the pressure change when a constant volume of gas at 2.00 atm is heated from 30.0 °C to 40.0 °C.

Expert's answer

1"^{st}" condition:

"P_1=2atm"

"T_1=30^0C" "=30+273.15=303.15K"

2"^{nd}" condition:

Let "P_2=P_2"

"T_2=40^0C=40+273.15=313.15K"

Now from the gas equation we know that

"P\\propto T"

Hence:

"\\dfrac{P_1}{P_2}=\\dfrac{T_1}{T_2}"

"P_2=2.067atm"

Now:

"\\Delta P=P_2-P_1"

"\\Delta P=2.067-2=0.067atm"

Learn more about our help with Assignments: Chemistry

## Comments

## Leave a comment