a- Combustion of 13.5 g of sample of an hydrocarbon yields 24.41 g CO, and 14.49 g H2O. The molar mass of the compound is 246 g/mol. What are the empirical and molecular formulas?
b- Balance the combustion equation using the molecular formula.
number of moles of hydrogen =
To get the whole number of mole we divide it by - 0.8714
we get moles of carbon = 1
we get moles of hydrogen = 1.84 = 2
multiplying by factor 2 to get the whole number-
we get empirical formula as =
Molecular formula = to find molecular formula , we determine how many empirical formula it takes to make 1 molecular formula =
molar mass of
molecular fomula will be
B) To balance the combustion equation using molecular formula-