Answer to Question #191378 in General Chemistry for Christine

Question #191378

A 4.0520g sample of HCl, sp. Gr 11.18,

required 44.15ml of 0.9035Mof Sodium

Hydroxide in titration, compute for

percent purity.


1
Expert's answer
2021-05-11T05:51:12-0400

The balanced chemical equation for above is:



Theoritical mass of given = 4.0520 gm


Percent purity


Now we have to find experimental mass,which is calculated by the reaction.

For

M=0.9035 M

V=44.15 ml

so by the formula of molarity




moles


Now we will calculate the experimental moles of HCl

From the reaction:

1 mole of NaOH gave 1 mole of HCl

hence 0.04 moles of NaOH will gave 0.04 moles of HCl


Hence the experimental mass of HCl

Experimental mass gm


Now percent purity


%





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