Question

A gas sample has a volume of 875 mL at 37^oC . What will the volume be at standard temperature?

Answer 1

Charles law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

$\frac {875}{310}=\frac {V_2}{273}$

$V_2= \frac {875×273}{310}=770.6 ml$