Answer to Question #186868 in General Chemistry for Adepoju Isaac

General Chemistry

Question #186868

Percentage purity of KOH in 6.50gdm

Expert's answer

Molar mass of KOH= 39+16+1=56g/mol

Since the solution contains 6.50g of KOH

Percentage purity= 6.50g/56g × 100%

= 11.6%

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