Question #182057

How many g of HNO_{3} would be needed to produce 34.6 L N_{2}O?

How many g Zn would be needed to produce 2.55 x 10^{24} molecules N_{2}O?

Expert's answer

**1)**

Assuming STP conditions,

"m(HNO_3)=34.6L(N_2O)\\times\\frac{1mol(N_2O)}{22.4L(N_2O)}\\times\\frac{10mol(HNO_3)}{1mol(N_2O)}\\times\\frac{63.01g(HNO_3)}{1mol(HNO_3)}=973g"

**Answer: **973 g

**2)**

"n(N_2O)=134.5g(Zn)\\times\\frac{1mol(Zn)}{65.38g(Zn)}\\times\\frac{1mol(N_2O)}{4mol(Zn)}=0.5143mol"

**Answer: **0.5143 mol

**3)**

"m(Zn)=125g(H_2O)\\times\\frac{1mol(H_2O)}{18.015g(H_2O)}\\times\\frac{4mol(Zn)}{5mol(H_2O)}\\times\\frac{65.38g(Zn)}{1mol(Zn)}=363g"

**Answer: **363 g

**4)**

"m(Zn)=2.55\\cdot10^{24}(molecules\\;N_2O)\\times\\frac{1mol(N_2O)}{6.022\\cdot10^{23}(molecules\\;N_2O)}\\times\\frac{4mol(Zn)}{1mol(N_2O)}\\times\\frac{65.38g(Zn)}{1mol(Zn)}=1110g"

**Answer: **1110 g

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