Question #181711

What energy in kcal is needed to change 15.0g of ice at -10°c to 15.0g of water at 0°c?

Expert's answer

The specific heat capacity of ice is 2.05 J/g^{o}C

The heat of fusion of water is 333.55 J/g

Therefore, the total heat equals:

"Q_{total}=c_{ice}m\\Delta{T}+c_fm=2.05J\/g\\cdot\\degree{C}\\times15.0g\\times(0\\degree{C}-(-10\\degree{C}))+333.55J\/g\\times15.0g=5310.75J"

"5310.75J\\times\\frac{1kJ}{1000J}\\times\\frac{1kcal}{4.1868kJ}=1.27kcal"

**Answer: **1.27 kcal

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