Answer to Question #99292 in Molecular Biology for amir

Question #99292
Rhodobacter lauracita is a newly discovered bacterium and is a manganesebased
photoautotrophy. Light provides the energy necessary to drive the
production of organic carbon. (Be careful, this question set is asking about
assimilation, rather than dissimilation reactions)
a. How much free energy in kJ/mol would be required to form one mole of
glucose (C6H12O6) if reduced manganese (Mn2+) served as the electron donor
for R. lauracita? Assume that Mn2+ is oxidized to the solid MnO2 (activity =
1), pH = 7, and that Mn2+ and glucose are present at 10-4 M. The partial
pressure of carbon dioxide is 10-3.5 atm. Give the answer in kJ per mole of
glucose produced.
E0’ (V)
1/2 MnO2(s) + 2 H+ + e- = 1/2 Mn2+ + H2O +0.58
1/4 CO2(g) + H+ + e- = 1/24 C6H12O6 + 1/4 H2O -0.43
Fe(OH)3(am) + 3 H+ + e- = Fe2+ + 3 H 2O +0.06
1
Expert's answer
2019-11-25T08:54:41-0500
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Comments

Assignment Expert
26.11.19, 13:56

Dear amir, your question requires a lot of work, which neither of our experts is ready to perform for free. We advise you to convert it to a fully qualified order and we will try to help you. Please submit it here https://www.assignmentexpert.com/submit

amir
26.11.19, 12:47

whay the answer still in progress

amir
23.11.19, 17:15

whay the answer still in progress

amir
23.11.19, 13:45

c. Another bacterial strain is added to the system that efficiently oxidizes Mn2+,
keeping the concentration of this substance very low. Explain qualitatively
how this affects your free energy yield for R. lauracita.

amir
23.11.19, 13:44

b. This bacterium can also grow with Fe2+ as the electron donor, which gets
oxidized to the amorphous solid Fe(OH)3(am) (activity = 1). Would you expect
R. lauracita to require less or greater light intensity for growth when grown on
iron (compared to manganese)? Assume pH = 1, and Fe2+ and glucose are
present at 10-4 M. The partial pressure of carbon dioxide is 10-3.5 atm. Justify
this quantitatively.



how abaout this one

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