# Answer to Question #69320 in Python for Jordan

Question #69320

# Given an integer n, return the number of digits of n.

def digitCount(n):

return 42

# Given an integer n, return the sum of its digits.

def digitSum(n):

return 42

# Definition: For a positive integer n, n factorial, denoted n!,

# is the product n*(n-1)*(n-2)*...*1. If n = 0, then define 0! as 1.

# Given an integer n (which you can assume is non-negative),

# return n! (n factorial).

def factorial(n):

return 42

# Definition: We say that m is a factor of n if m divides n without a remainder.

# Given an integer n (which you can assume is positive),

# return the smallest factor of n larger than 1.

# If n is 1, then you should return 1.

def smallestFactor(n):

return 42

def digitCount(n):

return 42

# Given an integer n, return the sum of its digits.

def digitSum(n):

return 42

# Definition: For a positive integer n, n factorial, denoted n!,

# is the product n*(n-1)*(n-2)*...*1. If n = 0, then define 0! as 1.

# Given an integer n (which you can assume is non-negative),

# return n! (n factorial).

def factorial(n):

return 42

# Definition: We say that m is a factor of n if m divides n without a remainder.

# Given an integer n (which you can assume is positive),

# return the smallest factor of n larger than 1.

# If n is 1, then you should return 1.

def smallestFactor(n):

return 42

Expert's answer

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