Answer to Question #22719 in Python for James

Question #22719
Given an int count of a number of donuts, return a string of the form 'donut 1,donut 2,..., donut <count>', where <count> is the number passed in. However, if the count is 5 or more, then use the string 'and <num> more donuts' as the last item instead of the actual list of donuts, where <num> is the number of remaining donuts So donuts(3) returns 'donut 1,donut 2,donut 3' donuts(4) returns 'donut 1,donut 2,donut 3,donut 4' donuts(10) returns 'donut 1,donut 2,donut 3,donut 4,and 6 more donuts' donuts(20) also returns 'donut 1,donut 2,donut 3,donut 4,and 16 more donuts' Python functions: range(), str() I have this so far, but I can't get the donut 1,donut 2, etc. def donuts(count): if count >= 5: count -= 4 numDonuts = 'and ' + str(count) + ' more donuts' else: numDonuts = 'donut ' + str(count) return numDonuts output: ‘donut 1’ ‘donut 1,donut 2,donut 3’ ‘donut 1,donut 2,donut 3,donut 4’ ‘donut 1,donut 2,donut 3,donut 4 and 6 more donuts’ ‘donut 1,donut 2,donut 3,donut 4 and 95 more donut
Expert's answer
Program is written on C++, using files.
#include <iostream>
#include <fstream>
using namespace std;

int main() {
ifstream in("input.txt");
ofstream out("output.txt");
for (int j=0; j<20; j++) {
int count;
in >> count;
if (count<5) {
for (int i=1;
i<=count; i++) {
(i==count) {

out << "donut " << i;

else {

out << "donut " << i <<
else {
for (int i=1; i<5;
i++) {
<< "donut " << i << ",";
out << "and
" << count << " more donuts";
out << endl;
return 0;

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