Answer to Question #8323 in C++ for eugine
In the first loop, you pop each item off the stack, and push it onto the temporary stack.
In the second loop, you pop each item off the temporary stack and push it onto both the original stack and the output stack.
If you can traverse the start from the bottom, then it isn't a stack copy operation, it's just a memory copy job.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!