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Answer to Question #7880 in C++ for Jun Park

Question #7880
Month Year Open High Low Close Avg Vol
December 2008 91.3 103.6 84.55 85.35 33800900
November 2008 105.93 111.79 79.14 92.67 44957200
October 2008 111.92 116.4 85 107.59 66902300
September 2008 172.4 173.5 100.59 113.66 43697600
August 2008 159.9 180.45 152.91 169.53 23273800
July 2008 164.23 180.91 146.53 158.95 33096200
June 2008 188.6 189.95 164.15 167.44 34281100
May 2008 174.96 192.24 172 188.75 32650300
April 2008 146.3 180 143.61 173.95 38841700
March 2008 124.44 145.74 118 143.5 42313100
February 2008 136.24 136.59 115.44 125.02 46645400
January 2008 199.27 200.26 126.14 135.36 62108100

In c programming, I have a text file like above but i'm wondering how i can extract only open and close column and store it as two dimension array.
Expert's answer
// Question7880.cpp : Defines the entry point for the console
application.
//

#include "stdafx.h"
#include
<stdio.h>
#include <stdlib.h>
#include
<string>
#include <iostream>
FILE *fr;
using namespace
std;
class Dat{
public:
char Month[900];
};

class
Obj{
public:
char Month[900];
};

void
opensafileintfile(){
Dat da[15];
Obj obj[15];
char line[900];
fr =
fopen ("data.txt", "rt"); /* open the file for reading */
fgets(line, 900,
fr);
printf("%s\n", line);
int count=0;
while(fgets(da[count].Month,
900, fr) != NULL)
{
//printf("%s\n", line);
count++;
}

int
c=0;
char line1[10];
float number;
char str[6];
for(int
i=0;i<70;i++){

if(da[0].Month[i]==' ' && da[0].Month[i+1]!='
'){
c++;
if(c==2){
str[0]=da[0].Month[i+1];
str[1]=da[0].Month[i+2];
str[2]=da[0].Month[i+3];
str[3]=da[0].Month[i+4];
str[4]=da[0].Month[i+5];
str[5]=da[0].Month[i+6];


}
}
}
cout<<str;

fclose(fr);
/* close the file prior to exiting the routine */
}
int _tmain(int argc,
_TCHAR* argv[])
{
int
a=0;
opensafileintfile();
scanf("%f",&a);
return 0;
}

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