Answer to Question #7241 in C++ for Andretti Rupert

Question

Can u please assist me in fixin this program?

#include <stdio.h>
#include <string.h>

main()
{
void enterdata(int y[]);
int y;
int i=0;
int choice;
void searchdata(int x[]);
char paint [9];
char colours [9];
char search[9];
int colour_no;
int r;
int x=0;

if(y>=5701||y<=5709)
printf("Choice Available:%d",enterdata);

if(y<5701||y>5709)
printf("Choice Not Available:%d",enterdata);

if(x!=-1)
printf("Colour Found:%s",colours);

if(x==-1)
printf("Colour Not Found:%s",colours);

}

void enterdata(int y[]){
int i;
if(i>=5701||i<=5709)
{
printf("Enter choice");
scanf("%d%",i);
}
else(i<5701||i>5709);
printf("Re-enter choice:");
{
if(i==5701)
{
printf("Red\n:");
}
if(i==5702)

Answer 1

#include <stdio.h>
#include <string.h>

void enterdata(int
y[], int size){
int i;
while(1){
printf("Enter choice:
");
scanf("%d",&i);
if(i<=5701||i>=5709)
break;
else{
printf("Re-enter choice\n");
switch (i){
case
5701:
printf("Red\n:");
break;
case 5202:
//something
happen
break;
//default: write it if you
need
}

}

}
for(int j=0; j<size;
j++){
scanf("%d",&y[j]);
}

}

int main()
{
int
y;
//...
char colours[9] ={'#','0','x','f','f','f','f','f','f'};
int
x=0;

printf("Enter choice:
");
scanf("%d",&y);

if(y>=5701||y<=5709) //you need to use
"&&" instead "||" for [5701;5709]
printf("Choice
Available:%d\n",enterdata);

if(y<5701||y>5709)
printf("Choice
Not Available:%d\n",enterdata);

if(x!=-1)
printf("Colour
Found:%s",colours);

if(x==-1)
printf("Colour Not
Found:%s",colours);
//...
return 0;// programm end successfully

}