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Answer to Question #70435 in C++ for Navya

Question #70435
Write a program that has a two-dimensional 3 by 5 integer array of gymnast scores in a competition. The scores must all be in the range of 0-10. Include nested loops to read in values into the array. Compute and print the average score for each gymnast in a seperate void function. Compute and print the overall score for each gymnast as well as the overall average(sum all 15 scores and divide by 15) in a seperate void function.

I have tried the problem but I don't know how to do the functions and everything messes up. I think there should be 5 gymnasts with three scores per each. Thank you!
Expert's answer
#include <iostream>
using namespace std;
void printGymnastAverage(int i, int score[]);
void printAverage(int score[][5]);
int main(void)
{
int score[3][5]; // two-dimensional 3 by 5 integer array of gymnast scores in a
competition
// nested loops to read in values into the array
for(int i=0; i<3; i++)
{
for(int j=0; j<5; j++)
{
int s;
do
{
cout << "Enter score " << (j+1);
cout << " for gymnast " << (i+1) << ": ";
cin >> s;
}while(s<0 || s>10); // The scores must all be in the range of 0-10
score[i][j] = s;
}
}
// Compute and print the average score for each gymnast
for(int i=0; i<3; i++)
{
printGymnastAverage(i, score[i]);
}
cout << endl;
// Compute and print the overall score for each gymnast as well as the overall average
//(sum all 15 scores and divide by 15)
printAverage(score);
return 0;
}
void printGymnastAverage(int i, int score[])
{
int sum = 0;
for(int j=0; j<5; j++)
{
sum += score[j];
}
cout << "Average score for gymnast " << (i+1) << " is : " << (double)sum/5.0 << endl;
}
void printAverage(int score[][5])
{
int sum = 0;
for(int i=0; i<3; i++)
{
for(int j=0; j<5; j++)
{
sum += score[i][j];
}
}
cout << "Overall Average score is : " << (double)sum/15.0 << endl;
}

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