Answer to Question #57103 in C++ for priyam
Question #57103
Write the output of the following C++ program code
void Location(int &X,int Y=4)
{
Y+=2;
X+=Y;
}
void main()
{
int PX=10,PY=2;
Location(PY);
cout<<PX<<”,”≪PY<<endl;
Location(PX,PY);
cout<<PX<<”,”≪PY<<endl;
}
void Location(int &X,int Y=4)
{
Y+=2;
X+=Y;
}
void main()
{
int PX=10,PY=2;
Location(PY);
cout<<PX<<”,”≪PY<<endl;
Location(PX,PY);
cout<<PX<<”,”≪PY<<endl;
}
Expert's answer
10,8
20,8
20,8
Need a fast expert's response?
Submit orderand get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Ask Your question
Thank you so much! The code was very well-written and clearly documented. I am very happy with the order!
#205308 on May 2018
#205308 on May 2018 
Comments
Next step, PX = 10 is passed by reference and PY by value. It means, only PX can change outside Location, PY will remain the same, 10. Changes of PX you can follow as described above.
Variables, passed by value does not change outside the function, because function works with their copy. Variables, passed by reference will change, because actually function works with the pointer to the original variable.
First you call Location(PY) which means you pass PY by reference. Thus, it takes PY = 2 and uses it as X variable. Inside Location, it increases value of Y: Y := Y + 2 ( = 6) and adds it to the current value of X ( = 2) obtaining 10. But X is the same as PY. Thus, PY becomes 10.
Function "Location" has two arguments, X passed by reference and Y passed by value. Moreover, Y has default value 4.
Could u explain ques#57103
Leave a comment