Answer to Question #57103 in C++ for priyam

Question #57103

Write the output of the following C++ program code
void Location(int &X,int Y=4)
{
Y+=2;
X+=Y;
}
void main()
{
int PX=10,PY=2;
Location(PY);
cout<<PX<<”,”≪PY<<endl;
Location(PX,PY);
cout<<PX<<”,”≪PY<<endl;
}

Expert's answer

10,8
20,8

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Assignment Expert

24.12.18, 19:21

Next step, PX = 10 is passed by reference and PY by value. It means, only PX can change outside Location, PY will remain the same, 10. Changes of PX you can follow as described above.

Assignment Expert

24.12.18, 19:20

Variables, passed by value does not change outside the function, because function works with their copy. Variables, passed by reference will change, because actually function works with the pointer to the original variable. First you call Location(PY) which means you pass PY by reference. Thus, it takes PY = 2 and uses it as X variable. Inside Location, it increases value of Y: Y := Y + 2 ( = 6) and adds it to the current value of X ( = 2) obtaining 10. But X is the same as PY. Thus, PY becomes 10.

Assignment Expert

24.12.18, 19:20

Function "Location" has two arguments, X passed by reference and Y passed by value. Moreover, Y has default value 4.

Yashita

24.12.18, 17:03

Could u explain ques#57103

Answer to Question #57103 in C++ for priyam

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