Answer to Question #49269 in C++ for Bradley

Question #49269
Could you explain how this code works.
for (int i = 0; i < 300; i++)
{
if ( i % 12 == 0)
{
cout << "i = " << i << endl;
}
Why it keeps adding by 12?
so int i is initialized to zero so i % 12 is 0
so it outputs
#: 0
so it goes back again and checks if i is less than 300
i % 12 is zero again but what's happening is it keeps adding by 12
it output like hits
#: 0
#: 12
#: 24
#: 48 and so on.
i becames 12?? does the 12 assigns to i?
1
Expert's answer
2014-11-25T01:15:17-0500
Solution.


for(int i = 0; i < 300; i++)
{
if ( i == 0)
{
cout << "i = " << i << endl;
}
}

dividend %divisor - Returns the remainder of oneexpression divided by another.

i
0=0, if(0==0){i=0}//Outputs 0 because the condition is fulfilled
1=1 //1 is not equal to0
2=2 //2 is not equal to0
3=3 //3 is not equal to0
4=4 //4 is not equal to0
….
12=0, if(0==0){i=12} //Outputs 12 because the condition is fulfilled
……
24=0, if(0==0){i=24} //Outputs 24 because the condition is fulfilled



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