Answer to Question #47964 in C++ for dustin records

Question

1+1/2+1/3+...+1/n
Write a program that compares the results of the
summation of the preceding series, computing from left to
right and from right to left with n = 50000

Answer 1

#include <iostream>
#include <cstdio>
int main() {
    int n = 50000;
    double sum1 = 0;
    double sum2 = 0;
    for (int i = 1; i <= n; i++) {
        sum1 += 1 / (double) i;
    }
    for (int i = n; i >= 1; i--) {
        sum2 += 1 / (double) i;
    }
    printf("Sum from left to right:  %f\n", sum1);
    printf("Sum from right to left:  %f", sum2);
}