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Answer to Question #40125 in C++ for Mary

Question #40125
Write, compile, execute, and test a program that uses the function templates
Square(),Power(),and Find() of Exercises 1,2,and 3.
1. Write a function template Square()that returns the square of its only argument.
2. Write a function template Power() that takes two arguments.The first argument
should be of arbitrary type. The second argument is an integer. The function
should return the first argument raised to the power indicated by its second argu-
ment.The return type should be that of its first argument.
3. Write a function template Find() that takes two arguments and returns an inte-
ger.The first argument is an array of arbitrary type.The second argument is an
ordinary variable of the same type as the first argument.The function should re-
turn the array subscript of the first array element that exceeds the second argu-
ment.If no such element is found,the function should return –1.
Expert's answer
#include<iostream>
#include <cstdlib> // system

template <typename T>
T Square(T value)
{
return value*value;
}

template <typename T>
T Power(T value, int i)
{
int const_value = value;
for (int j = 0; j < i - 1; j++)
value *= const_value;

return value;
}

template <typename T>
int Find(T array[], T element, int size_of_array)
{
bool exceeds_or_no = false;
int i = 0;
for (i = 0; i < size_of_array; i++)
if (array[i] > element) { exceeds_or_no = true; break; }

if (exceeds_or_no) return i;
else
return -1;

}

using namespace std;

int main()
{
int size_of_array = 0;
int value; int power;

cout<<"Enter value"<<endl;
cin>>value;
cout<<"value ^2 = "<<Square(value)<<endl;
cout<<"Enter power"<<endl;
cin>>power;
cout<<"value ^3 = "<<Power(value, power)<<endl;
cout<<"Enter size of array : "<<endl;
cin>>size_of_array;
int *array = new int[size_of_array];
cout<<"Enter elements of arrays : "<<endl;
for (int i = 0; i < size_of_array; i++)
cin>>array[i];
cout<<"Enter element"<<endl;
cin>>value;
cout<<"Array subscript : "<<Find(array, value , size_of_array)<<endl;
system("pause");
return 0;
}

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Comments

Assignment Expert
18.03.14, 17:31

Questions in this section are answered for free. We work on all questions
and publish answers after verification. There is no guarantee of answering
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Mary
18.03.14, 13:57

Why not??

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