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Answer to Question #37765 in C++ for Dil

Question #37765
Write a function that, using default arguments, allows user to take the sum of anywhere between 2 and 4 integers. This is what i got so far....#include <cstdlib>
#include <iostream>

using namespace std;


void sum(float a,float b);
void sum(int a,int b, int c = 0);
double sum(double a, double b, double c, double d);

int main(int argc, char *argv[])
{
int no[4];

cout<< "Enter any number from 2 to 4: "<<endl;

//Loop until EOF
for(int i=0; no[i]-1 != EOF; i++){
cout<< ">> ";
cin>> no[i]; //Ask value array no[]
i++;
}

sum(no[0],no[1],no[2],no[3]); //call function

system("PAUSE");
return EXIT_SUCCESS;
}
//FUNCTION
int sum(int a, int b){
return a + b;
}

float sum(float a, float b, float c){
return a + b + c;
}
double sum(double a, double b, double c, double d){
return a + b + c + d;
}

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Comments

Assignment Expert
16.12.13, 11:35

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Dils
14.12.13, 08:10

Didnt know it was this straight forward. Thank you!

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