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# Answer to Question #33482 in C++ for Uzair khan

Question #33482
write a complete c++ program that finds and show the number of occurrences in given string?
string is taken from user.
1
Expert's answer
2013-07-22T12:00:46-0400
#include <iostream>
#define lim 256
using namespace std;
char s1[lim];
char s2[lim];
char c;
int strlen(char s[])
{
int i = 0;
while (s[i] != '')
++i;
return i;
}
int numb_occurrences(char s_1[], char s_2[])
{
int n_o = 0; int n_c=0;
int i = 0; int j = 0;
while(s_1[i] != '')
{
if (s_2[j]!=s_1[i])
{
j = 0;
n_c = 0;
}
if (s_2[j] == s_1[i])
{
++n_c;
if (strlen(&s_2[0]) > n_c) j++;
if (strlen(&s_2[0]) == n_c) n_o++;
}
++i;
}
return n_o;
}
int main()
{
do
{
int i=0;
cout<<"Enter the string "<<endl;
for ( i=0; i<lim && (c = getchar())!= EOF && c!='
';++i)
s1[i]=c;
s1[i]='';
cout<<endl;
cout<<"Enter a search string (must not be longer than the first)"<<endl;
i=0;
for ( i=0; i<lim && (c = getchar())!= EOF && c!='
';++i)
s2[i]=c;
s2[i]='';
}
while (strlen(&s2[0]) > strlen(&s1[0]));
cout<<"The number of occurrences of the string 2 in line 1 : "<<numb_occurrences(&s1[0], &s2[0])<<endl;
system("pause");
return 0;
}

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