# Answer to Question #27147 in C++ for cwojo

Question #27147

A magic square is a square matrix of size n*n where n is an odd integer value, and that each of the integers 1,2,3,... n^2 (that is n squared) appears exactly once. The sum of each column and that of each row as well that of the diagonal must be equal. For example, given a 5*5 magic square, the sum of each row, each column and each diagonal must be equal to 65 and 175 for a 7*7 magic square. Write a program that can be used to accept any odd number as matrix size and output the corresponding magic square.

Expert's answer

#include <stdio.h>

#include <cstdlib>

using namespace std;

int main() {

//freopen ("input.txt", "r", stdin);

//freopen ("output.txt", "w", stdout);

int n;

scanf ("%d", &n);

if (n % 2 == 1) {

& for (int i = 1; i <= n; i++) {

for (int j = 1; j <= n; j++) {

printf ("%d ", 1 + n * ((i + j - 1 + (n - 1) / 2) % n) + (i + 2 * j - 2) % n);

}

printf ("\n");

& }

} else {

& printf ("Not odd number.\n");

}

return 0;

}

#include <cstdlib>

using namespace std;

int main() {

//freopen ("input.txt", "r", stdin);

//freopen ("output.txt", "w", stdout);

int n;

scanf ("%d", &n);

if (n % 2 == 1) {

& for (int i = 1; i <= n; i++) {

for (int j = 1; j <= n; j++) {

printf ("%d ", 1 + n * ((i + j - 1 + (n - 1) / 2) % n) + (i + 2 * j - 2) % n);

}

printf ("\n");

& }

} else {

& printf ("Not odd number.\n");

}

return 0;

}

## Comments

## Leave a comment