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# Answer to Question #25102 in C++ for eric

Question #25102
convert this c++ code in to assembly.. for (a=0; a&lt;=y; a++) for (b=0; b&lt;=y/2; b++) for (c=0; c&lt;=y/3; c++) if ((a + 2*b + 3*c) == y) count++;
1
2013-02-26T10:43:20-0500
.file &quot;asm.cpp&quot;
.text
.globl main
.type main, @function
main:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
subl $32, %esp movl$0, -20(%ebp)
jmp .L2
.L8:
movl $0, -16(%ebp) jmp .L3 .L7: movl$0, -12(%ebp)
jmp .L4
.L6:
movl -16(%ebp), %eax
leal (%eax,%eax), %edx
movl -20(%ebp), %eax
leal (%edx,%eax), %ecx
movl -12(%ebp), %edx
movl %edx, %eax
cmpl -4(%ebp), %eax
jne .L5
addl $1, -8(%ebp) .L5: addl$1, -12(%ebp)
.L4:
movl -4(%ebp), %ecx
movl $1431655766, %edx movl %ecx, %eax imull %edx movl %ecx, %eax sarl$31, %eax
movl %edx, %ecx
subl %eax, %ecx
movl %ecx, %eax
cmpl -12(%ebp), %eax
setge %al
testb %al, %al
jne .L6
addl $1, -16(%ebp) .L3: movl -4(%ebp), %eax movl %eax, %edx shrl$31, %edx
sarl %eax
cmpl -16(%ebp), %eax
setge %al
testb %al, %al
jne .L7
addl $1, -20(%ebp) .L2: movl -20(%ebp), %eax cmpl -4(%ebp), %eax setle %al testb %al, %al jne .L8 movl$0, %eax
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident &quot;GCC: (Ubuntu/Linaro 4.7.2-2ubuntu1) 4.7.2&quot;
.section .note.GNU-stack,&quot;&quot;,@progbits

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