# Answer to Question #24667 in C++ for alfred lontoc

Question #24667

3.Write a function integerPower(base, exponent) that returns the value of baseexponent. For example, integerPower(3,4) = 3 * 3 * 3 * 3. Assume that exponent is a positive, nonzero integer and that base is an integer. The function integerPower should use for or while to control the calculation. Do not use any math library functions. (exPo.cpp)

4.Write a function-oriented program that will perform date arithmetic; such as counting the total number of days between 6/1/1990 and 8/3/1992. (date.cpp)

4.Write a function-oriented program that will perform date arithmetic; such as counting the total number of days between 6/1/1990 and 8/3/1992. (date.cpp)

Expert's answer

#include <iostream>

#include <ctime>

int main()

{

struct tm t = { 0 };

t.tm_sec = t.tm_min = t.tm_hour = 0; // midnight

t.tm_mon = 0; // January

t.tm_year = 2012 - 1900;

t.tm_isdst = -1; // unknown

t.tm_mday = 200; // January 200th?

time_t when = mktime(&t);

const struct tm *norm = localtime(&when); // Normalized time

std::cout << "month=" << norm->tm_mon << ", day=" << norm->tm_mday << "\n";

std::cout << "The 200th day of 2012 starts " << asctime(norm);

}

#include <iostream>

#include <conio.h>

using namespace std;

long integerPower(int base, int exponent)

{

long result = 1;

while (exponent--)

& result *= base;

return result;

}

int main(int argc, char *argv[])

{

cout << "3 ^ 4 = " << integerPower(3, 4) << endl;

_getch();

return 0;

}

#include <ctime>

int main()

{

struct tm t = { 0 };

t.tm_sec = t.tm_min = t.tm_hour = 0; // midnight

t.tm_mon = 0; // January

t.tm_year = 2012 - 1900;

t.tm_isdst = -1; // unknown

t.tm_mday = 200; // January 200th?

time_t when = mktime(&t);

const struct tm *norm = localtime(&when); // Normalized time

std::cout << "month=" << norm->tm_mon << ", day=" << norm->tm_mday << "\n";

std::cout << "The 200th day of 2012 starts " << asctime(norm);

}

#include <iostream>

#include <conio.h>

using namespace std;

long integerPower(int base, int exponent)

{

long result = 1;

while (exponent--)

& result *= base;

return result;

}

int main(int argc, char *argv[])

{

cout << "3 ^ 4 = " << integerPower(3, 4) << endl;

_getch();

return 0;

}

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