Answer to Question #24196 in C++ for Nourh
10. What is wrong with the following code?
for (int i = 0; i < 10; i++) {
int x = 4;
cout << i << endl;
}
cout << x << endl;
1
2013-02-13T09:43:28-0500
your x value is a local variable, and is out ofsight, when you are trying to print it on screen after loop.
it is visible only inside loop!
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