Answer to Question #16432 in C++ for arif hussain

Question

Q#3 Write a program that creates four function calculator, so that it uses functions for each of the four arithmetic operations. They can be fadd, fsub, fmul, and fdiv. Each of these functions should take three arguments two of int type and one is of character type for the opera

Answer 1

#include<iostream>

#include<conio.h>

using namespace std;




struct fraction{int numerator; int denominator;};

fraction fadd(fraction a, fraction b);

fraction fsub(fraction a, fraction b);

fraction fmul(fraction a, fraction b);

fraction fdiv(fraction a, fraction b);




void main(void)

{



fraction f[3]; char c, op;



do{

cout<<"Enter your task : ";

cin >>f[0].numerator>>c>>f[0].denominator>>op>>f[1].numerator>>c>>f[1].denominator;

if(!f[0].denominator || !f[1].denominator) {cout<<"Illeagle fraction !"<<endl; op=false;}

switch(op) {

case '+':f[2]=fadd(f[0], f[1]); break;

case '-':f[2]=fsub(f[0], f[1]); break;

case '*':f[2]=fmul(f[0], f[1]); break;

case '/':f[2]=fdiv(f[0], f[1]); break;

default:cout<<"Unknow operator please try again !"<<endl;}

cout<<"Answer = "<<f[2].numerator<<c<<f[2].denominator;

cout<<"

!Press c to continue or any key to exit."<<endl<<endl;

}while(getch()=='c');

}




fraction fadd(fraction a, fraction b){

fraction f;

f.numerator =a.numerator*b.denominator+a.denominator*b.numerator;

f.denominator=a.denominator*b.denominator; return f;}




fraction fsub(fraction a, fraction b){

fraction f;

f.numerator =a.numerator*b.denominator-a.denominator*b.numerator;

f.denominator=a.denominator*b.denominator; return f;}




fraction fmul(fraction a, fraction b){

fraction f;

f.numerator =a.numerator*b.numerator;

f.denominator=a.denominator*b.denominator; return f;}




fraction fdiv(fraction a, fraction b){

fraction f;

if(b.numerator != 0){

f.numerator =a.numerator*b.denominator;

f.denominator=b.numerator*a.denominator;}

else cout<<"Math error !"<<endl; return f;}