Answer to Question #15973 in C++ for judith

Question

Your city's Parking Violations Bureau wants you to write a program for computer fines for parking violations. There are four types of violations: type A car carries a fine of $10,type B carries a find of $20,type C carries a fine of $30, and type D carries a fine of$50. The program should ask for the number of type A,B or C violations, the number of type B violations, and so on. If the number of type A,B, or C violations exceeds 10,impose an additional$50 fine for each category that exceeds 10. If the total number of type A,B or individually exceeds 10, impose and additional fine of$75. If the number of type D violations exceeds 3, impose an additional fine of $20 for each type D violation over three. The program should display the total fine for the person. The program should process any number of persons.

Answer 1

#include "stdafx.h"
#include <iostream>
#include
<iomanip>
using namespace std;

int main()
{
const double
TYPEA = 10, TYPEB = 20, TYPEC = 30, TYPED = 50;
double result1, result2,
Total,typeA, typeB, typeC, typeD, finA, finB, finC;
finC=0;
cout <<
setprecision(2)
<< setiosflags(ios::fixed)
<<
setiosflags(ios::showpoint);

// Obtain Input
result1=0;
cout
<< "Enter total number of A violations: ";
cin >> typeA;
if
(typeA >= 10)
finA = (typeA * TYPEA + 50);
else
finA = (typeA *
TYPEA);

cout << "Enter total number of B violations: ";
cin
>> typeB;
if (typeB >= 10)
finB = (typeB * TYPEB +
50);
else
finB = (typeB * TYPEB);

cout << "Enter total number
of C violations: ";
cin >> typeC;
if (typeC >= 10)
finC =
(typeC * TYPEC + 50);
else
finA = (typeC * TYPEC);

result1 = (finA
+ finB + finC);

if (result1 >= 20)
(result1 + 75);


cout
<< "Enter total number of D violations: ";
cin >>
typeD;
result2=0;
if (typeD >= 3)
(typeD * TYPED +
20);
else{
result2 = (typeD + TYPED);
}


//Display
results

cout << endl << endl;
cout << "The total
fine for A, B, and C violations is " << result1 << endl;
cout
<< "The total fine for D violations is " << result2 <<
endl;

Total = (result1 + result2);

cout << "The total of all
violations:" << Total << endl;


system
("PAUSE");

return 0;
}