# Answer to Question #15342 in C++ for reymark

Question #15342

write a program that will accept a number n and display the sum of all even numbers and the sum of all odd numbers from 1 to n.

Expert's answer

#include<iostream.h>

bool even(int n){

if (n%2==0) return true; else return 0;

}

int sumOdd=0, sumEven=0;

void main(){

int m;

cout<<"Enter an integer: ";

cin>>m;

for (int i=0; i<=m; i++)

& if (even(i)) sumEven += i;

& else sumOdd += i;

cout<<"Sum of even numbers: "<<sumEven<<"\nSum of odd numbers: "<<sumOdd<<"\n";

}

bool even(int n){

if (n%2==0) return true; else return 0;

}

int sumOdd=0, sumEven=0;

void main(){

int m;

cout<<"Enter an integer: ";

cin>>m;

for (int i=0; i<=m; i++)

& if (even(i)) sumEven += i;

& else sumOdd += i;

cout<<"Sum of even numbers: "<<sumEven<<"\nSum of odd numbers: "<<sumOdd<<"\n";

}

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