Answer to Question #15220 in C++ for chinatsu

Question

what does the line below do?

!wordFlag

int words(const char sentence[ ]){
int numberOfWords=0;
int wordFlag=0;
char* pointer=sentence;
while ((*pointer)!=NULL)
{
if(((*pointer)!=' ')&&((*pointer)!='\n')&&((*pointer)!='\t')&&(!wordFlag))

{
numberOfWords++;
wordFlag=1;
}
if(!(((*pointer)!=' ')&&((*pointer)!='\n')&&((*pointer)!='\t')))
{
wordFlag=0;
}
pointer++;
}
return numberOfWords;
}

Answer 1

#include <iostream>
#include <conio.h>
using namespace std;

int words(char sentence[]){
int numberOfWords=0;
int wordFlag=0;
char* pointer=sentence;
while ((*pointer)!=NULL) {
if(((*pointer)!=' ')&&((*pointer)!='
')&&((*pointer)!=' ')&&(!wordFlag)) {
numberOfWords++;wordFlag=1; }
if(!(((*pointer)!=' ')&&((*pointer)!='
')&&((*pointer)!=' '))) {
wordFlag=0; }
pointer++; }
return numberOfWords;
}

int main ()
{
char sentence[] = "abcdefd";
cout << words(sentence);
system("pause");
return 0;
}