# Answer to Question #14048 in C++ for shalenee

Question #14048

(Demonstrating cancellation errors) A cancellation error

occurs when you are manipulating a very large number with a

very small number. The large number may cancel out the

smaller number. For example, the result of 100000000.0 +

0.000000001 is equal to 100000000.0. To avoid cancellation

errors and obtain more accurate results, carefully select

the order of computation. For example, in computing the

following series, you will obtain more accurate results by

computing from right to left rather than from left to

right:

1+1/2+1/3+...+1/n

Write a program that compares the results of the

summation of the preceding series, computing from left to

right and from right to left with n = 7000.

occurs when you are manipulating a very large number with a

very small number. The large number may cancel out the

smaller number. For example, the result of 100000000.0 +

0.000000001 is equal to 100000000.0. To avoid cancellation

errors and obtain more accurate results, carefully select

the order of computation. For example, in computing the

following series, you will obtain more accurate results by

computing from right to left rather than from left to

right:

1+1/2+1/3+...+1/n

Write a program that compares the results of the

summation of the preceding series, computing from left to

right and from right to left with n = 7000.

Expert's answer

#include <iostream>

using namespace std;

int main()

{

double leftToRight = 0, rightToLeft = 0;

int n = 7000;

cout

<< "SUM( 1 / i), i in (1 .. 7000)" << endl;

for(int i = 1, j

= n; i <= 7000; ++i, --j)

{

leftToRight += 1.0 / i;

rightToLeft += 1.0 / j;

}

cout << "Left to right: "

<< leftToRight << endl;

cout << "Right to left: "

<< rightToLeft << endl;

getchar();

return 0;

}

using namespace std;

int main()

{

double leftToRight = 0, rightToLeft = 0;

int n = 7000;

cout

<< "SUM( 1 / i), i in (1 .. 7000)" << endl;

for(int i = 1, j

= n; i <= 7000; ++i, --j)

{

leftToRight += 1.0 / i;

rightToLeft += 1.0 / j;

}

cout << "Left to right: "

<< leftToRight << endl;

cout << "Right to left: "

<< rightToLeft << endl;

getchar();

return 0;

}

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