Answer to Question #12766 in C++ for Roger

Question #12766
float Median; for (int j = 0; j &lt; m; j++) { for (int i = 0; i &lt; j; i++) { if (array[j] &lt; array[i]) { int temp = array[j][i]; array[j][i] = array[i][j]; array[i][j] = temp; } } } for (int j = 0; j &lt; m; j++) { if (n % 2 == 0) { int i = 0; Median = ((array[i][j]/2) + (array[i][j]/2)-1)/2; cout &lt;&lt; Median &lt;&lt; endl; } if (n % 2 != 0) { int i = 0; Median = array[i][j]/2; cout &lt;&lt; Median &lt;&lt; &quot;\n\n&quot;; } } cout &lt;&lt; &quot;The Median of each row is displayed above.\n\n&quot;; } } return 0; } I have been having lots of trouble trying to get the Median of each row in a 2D array. Note that m is the variable that represents the length of a row and n is the variable that represents the length of a column. The user had chose these variables earlier in the program. Also note that array[i][j] was what stored the lengths as well as the numbers the user wanted to put in the matrix. This is also earlier in the program. If I wanted to find the median of each row starting with row 1 and going to row m, how would I go about that?
float Median=0;
for (int i=0; i<n; i++){
for (int j=0; j<m;
j++){
Median=Median+array[i][j];
}

Median=Median/m;
cout<<Median<< "\n\n";

Median=0;
}
cout <<"The Median of each row is displayed
above.\n\n";
return 0;
}

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