Answer to Question #12766 in C++ for Roger

Question

float Median;

for (int j = 0; j < m; j++)
{
for (int i = 0; i < j; i++)
{
if (array[j] < array[i])
{
int temp = array[j][i];
array[j][i] = array[i][j];
array[i][j] = temp;
}
}
}

for (int j = 0; j < m; j++)
{
if (n % 2 == 0)
{
int i = 0;
Median = ((array[i][j]/2) + (array[i][j]/2)-1)/2;
cout << Median << endl;
}

if (n % 2 != 0)
{
int i = 0;
Median = array[i][j]/2;
cout << Median << "\n\n";
}
}
cout << "The Median of each row is displayed above.\n\n";
}

}
return 0;
}

I have been having lots of trouble trying to get the Median of each row in a 2D array. Note that m is the variable that represents the length of a row and n is the variable that represents the length of a column. The user had chose these variables earlier in the program. Also note that array[i][j] was what stored the lengths as well as the numbers the user wanted to put in the matrix. This is also earlier in the program. If I wanted to find the median of each row starting with row 1 and going to row m, how would I go about that?

Answer 1

float Median=0;
for (int i=0; i<n; i++){
for (int j=0; j<m;
j++){
Median=Median+array[i][j];
}

Median=Median/m;
cout<<Median<< "\n\n";

Median=0;
}
cout <<"The Median of each row is displayed
above.\n\n";
return 0;
}