Answer to Question #10867 in C++ for Jo

Question #10867
The program below (in C not in C++) reads a double before calling the chop function, which has the following prototype: void chop(double d, long *whole_part, double *fraction_part); This function chops the double into two parts, the whole part and the fraction. So “365.25” would be chopped into “365” and “.25”. Implement the function. #include <stdio.h> #include <math.h> #include <limits.h> void chop(double d, long *whole_part, double *fraction_part); int main(void) { double d = 0.0; long whole = 0; double fraction = 0.0; printf("enter a double "); scanf("%lf", &d); chop(d, &whole, &fraction); printf("%lf chopped is %ld and %.5lg\n", d, whole, fraction); return 0; } void chop(double d, long *whole_part, double *fraction_part) { Insert the function here }
1
Expert's answer
2012-11-12T08:16:33-0500
int main(void)
{
& double d = 1.5;
& double i = 0;
& double f = modf(d, &i);
& printf("Number = %g\n", d);
& printf("Integer part = %g, fractional part = %g\n", i, f);
& return 0;
}

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