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Answer to Question #70886 in C for Prabhat

Question #70886
#include<stdio.h>
int main ()
{
int n;
for(n=7;n!=0;n--)
printf("n= %d",n--);
return 0;
}





Kindly explain it's output...
Expert's answer
This program will work infinitely, and it will output reducing values with step -2 from 7 till -2147483647 after that it will output reducing values from 2147483647 till -2147483647 infinitely.
All this happends due to unreachable condition of the loop finish using step -2 with passing 0 value (7, 5, 3, 1, -1, -3, ...).

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