Answer to Question #28691 in C# for Mohammad
if ((e.Modifiers & Keys.Shift) == Keys.Shift)
lbl.Text += "\n" + "Shift was held down.";
bits are 1, the corresponding result bit is set to 1. Otherwise, the
corresponding result bit is set to 0.
In this case, condition "if (( a & b ) ==b)" is TRUE, when a>=b. This construction may be used with 2-byte
variables, when most significant bit is a key, least - modifiers.
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