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Answer to Question #1581 in C# for CALEB ADEYMO

Question #1581
Want to write a C# progm creating a Rectangle class to have two variables length and width. Two constructors are needed, the default constructor should intialize length and width to 1.0 each. The second must pass in two values to initialize length and width. There must be six methods to do the following: SetLength,SetWidth,GetLength,GetWidth, GetArea, and GetPerimeter.The perimeter is the sum of all sides of a rectangle. Three instances of the Rectangle needs to be created. The first rectOne must use the se
Expert's answer
using System;namespace Application
{
public class Rectangle
{
private double length;
private double width;

public Rectangle ()
{
length = 1.0;
width = 1.0;
}

public Rectangle (double l,double w)
{
length = l;
width = w;
}

public void SetLength(double l){
length = l;
}

public void SetWidth(double w){
width = w;
}

public double GetLength(){
return length;
}

public double GetWidth(){
return width;
}

public double GetArea(){
return length*width;
}

public double GetPerimeter(){
return (length+width)*2;
}

static void Main(string[] args){
Rectangle rectOne = new Rectangle();
Console.WriteLine("Area: "+rectOne.GetArea());
Console.WriteLine("Perimeter: "+rectOne.GetPerimeter());
Rectangle rectTwo = new Rectangle(2.0,4.0);
Console.WriteLine("Area: "+rectTwo.GetArea());
Console.WriteLine("Perimeter: "+rectTwo.GetPerimeter());
Rectangle rectThree = new Rectangle(5.0,10.0);
Console.WriteLine("Area: "+rectThree.GetArea());
Console.WriteLine("Perimeter: "+rectThree.GetPerimeter());
}
}
}

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Comments

Assignment Expert
21.06.11, 16:29

You are always welcome!

Assignment Expert
21.06.11, 16:24

We have a lot of experts ready for helping you.

Assignment Expert
21.06.11, 16:22

Welcome))

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