Answer to Question #368 in Assembler for abdul rehman
Suppose that a certain program takes 500 seconds of elapsed time to execute. Out of these 500 seconds, 280 seconds is the CPU time and the rest is I/O time. What will be the I/O time?
I/O time = Elapsed time to execute - CPU time. So I/O time is 500 seconds - 280 seconds = 220 seconds.
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