Answer to Question #87736 in Quantum Mechanics for Sridhar

Quantum Mechanics

Question #87736

The orbital angular momentum of a single 2s electron is (h is the
Planck’s constant) :
(A) h/2
(B) h/4
(C) h√ 2 / 2
(D) Zero

Expert's answer

Orbital angular momentum:

"L=\\frac{\\sqrt{l(l+1)}h}{2 \\pi}"

For s-orbital:

"l=0"

Thus,

"L=0"

Answer: (D) Zero.

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