Answer to Question #55946 in Quantum Mechanics for MAYANK SHARMA

Question #55946
An electron has de broglie wavelength equal to that of a photon. Show that the ratio of the kinetic energy of the electron to the energy of the photon is (m2c4+h2v2)1/2-mc2/hv
Expert's answer

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal