# Answer on Quantum Mechanics Question for Patricia

Question #1285

An x-ray photon of the maximum energy produced by a tube leaves the tube and collides elastically with an electron at rest. As a result, the electron recoils and the x-ray is scattered. The frequency of the scattered x-ray photon is 1.64x10^19Hz. Relativistic effects may be neglected for the electron.

Determine the kinetic energy of the recoiled electron and the magnitude of its momentum.

Determine the kinetic energy of the recoiled electron and the magnitude of its momentum.

Expert's answer

We need to know the initial energy of the X-ray photon W

Then we can use the Law of Energy conservation and the Law of Momentum conservation:

W

The momentum of the photon can be found

p = hf/c = W/c, where c- is the speed of the light.

Thus

W

_{1}.Then we can use the Law of Energy conservation and the Law of Momentum conservation:

W

_{1}= E_{e}+ W_{2}, where W_{2}= hf_{2}(h - is Plank's constant, f - frequency), f_{2}= 1.64x10^{19}Hz.**E**._{e}= W_{1}- hf_{2}The momentum of the photon can be found

p = hf/c = W/c, where c- is the speed of the light.

Thus

W

_{1}/c = p_{e}+ hf_{2}/c;**p**_{e}= W_{1}/c - hf_{2}/cNeed a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment